The product of the page numbers on two facing pages of a book is 306. Find the page numbers.?

Let the consecutive page numbers be x and x+1. Then:


(x)(x+1) = 306





Distribute:


x^2 + x = 306





Subtract 306 from both sides:


x^2 + x - 306 = 0





Factor:


(x + 18)(x - 17) = 0


x = -18 or x = 17


(can't be negative!)





So the page numbers are 17 and 18.

The product of the page numbers on two facing pages of a book is 306. Find the page numbers.?
n(n + 1) = 306


n² + n - 306 = 0


(n - 17)(n + 18) = 0


n = 17 or -18





The pages must be 17 and 18. However, note that odd numbered pages are always on the right, so this does not reflect a real-world book.
Reply:The page numbers of two facing pages will be consecutive numbers.Let them be 'x' and 'x+1'.





Given


their product = 306





x(x+1) = 306





x^2 + x = 306





x^2 + x - 306 = 0





(x+18)(x-17) = 0





x+18 = 0 (or) x-17 = 0





x = -18 (or) x =17





Page number cannot be negative.





So x = 17





x+1 = 18





So, the page numbers are 17 and 18.
Reply:x(x+1)=306


x^2+x-306=0





Quadratic formula..
Reply:x = 1st page, x + 1 = 2nd page





Finding the no. of the 1st page:


x(x + 1) = 306


x² + x = 306


x² + x - 306 = 0


(x + 18)(x - 17) = 0


We choose the factor that will yield a positive number for x.


x - 17 = 0, x = 17





Page no. of the 2nd page:


= 17 + 1


= 18





Answer: The page numbers are 17 and 18.
Reply:17 and 18!!!!!!!!