A student opens a mathmatics book to two facing pages. The product of the page numbers is 1640.?

Find the page numbers.


The first page is_.


The second page is_.

A student opens a mathmatics book to two facing pages. The product of the page numbers is 1640.?
x(x+1)=1640





x^2+x-1640=0





(x+41)(x-40)=0





Your page numbers are 40 and 41.
Reply:40 and 41
Reply:Let x = first page


Let x + 1 = second page


x(x + 1) = 1640


x^2 + x - 1640


(x + 41)(x - 40) = 0


x = -41, 40


since page numbers are not negative, x = 40


The second page is x + 1 = 41
Reply:From the problem we know that:





x * y = 1640 Where x left page and y = right page.





We also know that:





x+1 = y Substituting x + 1 for y in the first equation gives us:





x * (x+1) = 1640 Do math on left side:





x^2 + x = 1640 Put in quadratic form





x^2 + x -1640 = 0 Using the quadratic equation we get:





(-1 +/- sqr(1^2 - 4 * 1 * -1640)/2 * 1 or





(-1 +/- sqrt(6561))/2 or





(-1 +/- 81) / 2 Which gives us two answers:





(-1 - 81)/2 or





- 42 which we can ignore as you cant have negative page numbers





We also get:





(-1+81)/2 = 40 Which gives us the value of x the first page.





Adding 1 to that we get 41, the second page.





Long answer for a simple question.
Reply:Let x be the lower page number


Let (x+1) be the next page number.





x(x+1) = 1640





x^2 + x = 1640





x^2 + x - 1640 = 0





(x-40)(x+41) = 0





x = -41 or x = 40





x = -41 is inadmissible





therefore, the page numbers are 40 and 41
Reply:40


41





40 X 41 = 1640
Reply:The page numbers are 40 and 41.
Reply:40 and 41

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